A 1200 kg car enters a round about (Area = 81 π) with velocity of 20 m/s, 1) find the Centripetal acceleration of the car. 2)find the required force to keep the car in it’s path
A=81π=2πr→r=40.5 (m)A=81\pi=2\pi r\to r=40.5\ (m)A=81π=2πr→r=40.5 (m)
1)
a=v2/r=202/40.5=9.88 (m/s2)a=v^2/r=20^2/40.5=9.88\ (m/s^2)a=v2/r=202/40.5=9.88 (m/s2)
2)
F=mv2r→F=1200⋅9.88=11852 (N)F=m\frac{v^2}{r}\to F=1200\cdot9.88=11852\ (N)F=mrv2→F=1200⋅9.88=11852 (N) . Answer
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