Show that Gauss’ Law can be used to have an equation that shows the capacitance of two parallel plates in a vacuum.
∫EdA=1ϵ0∑qi→E=qϵ0A\int EdA=\frac{1}{\epsilon_0}\sum{q_i\to E=\frac{q}{\epsilon_0A}}∫EdA=ϵ01∑qi→E=ϵ0Aq
V=EdV=EdV=Ed
C=qV=qEd=ϵ0Aqqd=ϵ0AdC=\frac{q}{V}=\frac{q}{Ed}=\frac{\epsilon_0Aq}{qd}=\frac{\epsilon_0A}{d}C=Vq=Edq=qdϵ0Aq=dϵ0A . Answer
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