An open at both ends pipe has a length of 50cm. What are three lowest
frequencies to which it will resonate? v=340m/s]
f=nv2Lf=\frac{nv}{2L}f=2Lnv
f1=1⋅3402⋅0.5=340 (Hz)f_1=\frac{1\cdot 340}{2\cdot 0.5}=340\ (Hz)f1=2⋅0.51⋅340=340 (Hz)
f2=2⋅3402⋅0.5=680 (Hz)f_2=\frac{2\cdot 340}{2\cdot 0.5}=680\ (Hz)f2=2⋅0.52⋅340=680 (Hz)
f3=3⋅3402⋅0.5=1020 (Hz)f_3=\frac{3\cdot 340}{2\cdot 0.5}=1020\ (Hz)f3=2⋅0.53⋅340=1020 (Hz)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments