light of wavelength 589.3nm falls normally on a plane transmission grating having 600 lines/cm. calculate the angle at which the principal maxima of the first order form
"d\\sin\\theta=m\\lambda"
"d=\\frac{0.01}{600}=1.67\\cdot10^{-5}\\ (m)"
"\\theta=\\sin^{-1}(m\\lambda\/d)=\\sin^{-1}(1\\cdot589.3\\cdot10^{-9}\/1.67\\cdot10^{-5})\\approx2\u00b0" . Answer
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