Question #161270

Two free point charges +q and +4q are a distance L apart. A third charge is 

placed so that the entire system is in equilibrium. Find the location, 

magnitude and sign of the third charge.



1
Expert's answer
2021-02-04T11:42:50-0500

kq4qL2=kqq0x2k\frac{q\cdot 4q}{L^2}=k\frac{q\cdot q_0}{x^2}


and


kq4qL2=k4qq0(Lx)2k\frac{q\cdot 4q}{L^2}=k\frac{4q\cdot q_0}{(L-x)^2}


We have


kqq0x2=k4qq0(Lx)23x2+2LxL2=0x=L/3k\frac{q\cdot q_0}{x^2}=k\frac{4q\cdot q_0}{(L-x)^2} \to 3x^2+2Lx-L^2=0\to x=L/3 to the right of the charge qq . Answer


kq4qL2=kqq0(L/3)2q0=49qk\frac{q\cdot 4q}{L^2}=k\frac{q\cdot q_0}{(L/3)^2}\to q_0=-\frac{4}{9}q . Answer










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