Two free point charges +q and +4q are a distance L apart. A third charge is
placed so that the entire system is in equilibrium. Find the location,
magnitude and sign of the third charge.
"k\\frac{q\\cdot 4q}{L^2}=k\\frac{q\\cdot q_0}{x^2}"
and
"k\\frac{q\\cdot 4q}{L^2}=k\\frac{4q\\cdot q_0}{(L-x)^2}"
We have
"k\\frac{q\\cdot q_0}{x^2}=k\\frac{4q\\cdot q_0}{(L-x)^2} \\to 3x^2+2Lx-L^2=0\\to x=L\/3" to the right of the charge "q" . Answer
"k\\frac{q\\cdot 4q}{L^2}=k\\frac{q\\cdot q_0}{(L\/3)^2}\\to q_0=-\\frac{4}{9}q" . Answer
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