Question #161226

 A torsional pendulum is formed by attaching a wire to the center of a meter stick with mass 2.0 kg. If the resulting period is 3.0 minutes, what is the torsion constant for the wire?


1
Expert's answer
2021-02-04T19:09:23-0500

The period of the torsional pendulum is:


T=2πIκT = 2\pi\sqrt{\dfrac{I}{\kappa}}

where II is the moment of inertia, and κ\kappa is the torsion constant. The moment of inertial of the meter stick (l=1ml = 1m) about its center is:


I=ml212I = \dfrac{ml^2}{12}

where m=2kgm = 2kg is the mass of the stick. Substituting this into the first formula and expressing κ\kappa, find:


κ=π2l2m3T2\kappa = \dfrac{\pi^2l^2m}{3T^2}

since T=3min=180sT = 3min = 180s, obtain:


κ=π2122318022.03×104m2kg/s2\kappa = \dfrac{\pi^21^2\cdot 2}{3\cdot 180^2} \approx 2.03\times 10^{-4} m^2\cdot kg/s^2

Answer. 2.03×104m2kg/s22.03\times 10^{-4} m^2\cdot kg/s^2.


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