Question #160842

3. The body weighing 2.5kg is hung on the hook of a dynamometer. Find: a) The weight of the body when the body and the dynamometer are at rest. b) Body weight when together with the dynamometer they climb up with an acceleration of 5m / s²


1
Expert's answer
2021-02-08T18:42:43-0500

a)

W=mg=2.5 kg9.8 ms2=24.5 N.W=mg=2.5\ kg\cdot9.8\ \dfrac{m}{s^2}=24.5\ N.

b)

Nmg=ma,N-mg=ma,N=m(g+a)=2.5 kg(9.8 ms2+5.0 ms2)=37 N.N=m(g+a)=2.5\ kg\cdot(9.8\ \dfrac{m}{s^2}+5.0\ \dfrac{m}{s^2})=37\ N.

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