A 50 kg shell is fired from a cannon on Earth's surface with a potential energy of 196,000 J. What is the shell's maximum height?
PE=mgh→h=PEmg=19600050⋅9.8=400(m)PE=mgh\to h=\frac{PE}{mg}=\frac{196000}{50\cdot9.8}=400(m)PE=mgh→h=mgPE=50⋅9.8196000=400(m) . Answer
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