Question

A 50 kg skydiver loses 2400 kJ of energy during a jump. What was her change in height?

Answer 1

$$PE_{loss}=mg\Delta h,$$ $$\Delta h=\dfrac{PE_{loss}}{mg}=\dfrac{2.4\cdot10^6\ J}{50\ kg\cdot9.8\ \dfrac{m}{s^2}}=4900\ m.$$