Answer to Question #160726 in Physics for brayden battavio

Question #160726

A 0.02 kg rock strikes the ground with 0.36 J of kinetic energy. What was its velocity?

Expert's answer

"KE=\\dfrac{1}{2}mv^2,""v=\\sqrt{\\dfrac{2KE}{m}}=\\sqrt{\\dfrac{2\\cdot0.36\\ J}{0.02\\ kg}}=6\\ \\dfrac{m}{s}."

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