A scalar of temperature T is given by, T= x2 + y2 +z2 . Calculate the gradient (∇T) of the scalar function at (1, 1, 2).
∇ T=∂T∂xi→+∂T∂yj→+∂T∂zk→=\nabla\ T=\frac{\partial T}{\partial x}\overrightarrow{i}+\frac{\partial T}{\partial y}\overrightarrow{j}+\frac{\partial T}{\partial z}\overrightarrow{k}=∇ T=∂x∂Ti+∂y∂Tj+∂z∂Tk=
=2xi→+2yj→+2zk→=2⋅1⋅i→+2⋅1⋅j→+2⋅2⋅k→==2x\overrightarrow{i}+2y\overrightarrow{j}+2z\overrightarrow{k}=2\cdot1\cdot \overrightarrow{i}+2\cdot1\cdot \overrightarrow{j}+2\cdot2\cdot \overrightarrow{k}==2xi+2yj+2zk=2⋅1⋅i+2⋅1⋅j+2⋅2⋅k=
=2⋅i→+2⋅j→+4⋅k→=2\cdot \overrightarrow{i}+2\cdot \overrightarrow{j}+4\cdot \overrightarrow{k}=2⋅i+2⋅j+4⋅k . Answer
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