Question #159840

A scalar of temperature T is given by, T= x2 + y2 +z2 . Calculate the gradient (∇T) of the scalar function at (1, 1, 2).


1
Expert's answer
2021-02-02T09:32:11-0500

 T=Txi+Tyj+Tzk=\nabla\ T=\frac{\partial T}{\partial x}\overrightarrow{i}+\frac{\partial T}{\partial y}\overrightarrow{j}+\frac{\partial T}{\partial z}\overrightarrow{k}=


=2xi+2yj+2zk=21i+21j+22k==2x\overrightarrow{i}+2y\overrightarrow{j}+2z\overrightarrow{k}=2\cdot1\cdot \overrightarrow{i}+2\cdot1\cdot \overrightarrow{j}+2\cdot2\cdot \overrightarrow{k}=


=2i+2j+4k=2\cdot \overrightarrow{i}+2\cdot \overrightarrow{j}+4\cdot \overrightarrow{k} . Answer




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