Determine the angular momentum of a 72-gg particle about the origin of coordinates when the particle is at xxx = 5.0 mm , yyy = -5.8 mm , and it has velocity υ=(3.1i^−8.2k^)m/sυ=(3.1i^−8.2k^)m/s.Find the xx-component.
L→=[r→,p→]=m[r→,v→]=\overrightarrow{L}=[\overrightarrow{r},\overrightarrow{p}]=m[\overrightarrow{r},\overrightarrow{v}]=L=[r,p]=m[r,v]=
=0.072⋅[(0.005i→−0.0058j→),(3.1i→−8.2k→)]==0.072\cdot[(0.005\overrightarrow{i}-0.0058\overrightarrow{j}),(3.1\overrightarrow{i}-8.2\overrightarrow{k})]==0.072⋅[(0.005i−0.0058j),(3.1i−8.2k)]=
=0.0034i→+0.0029j→+0.0013k→=0.0034\overrightarrow{i}+0.0029\overrightarrow{j}+0.0013\overrightarrow{k}=0.0034i+0.0029j+0.0013k . Answer
Lx=0.0034 (kg⋅m2/s)L_x=0.0034\ (kg\cdot m^2/s)Lx=0.0034 (kg⋅m2/s) . Answer
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