Answer to Question #159480 in Physics for buddy

Question

An 18.3 kg potted plant is put on a 24.4 kg wooden table. The table and the floor do not budge. a. What is the normal force of the table on the potted plant?

b. What is the normal force of the floor on all of the table legs in total?

Answer 1

a)

$$N_1=(m_1)g\\N_1=(18.3)9.8=179\ N$$

b)

$$N_2=(m_1+m_2)g\\N_2=(18.3+24.4)9.8=418\ N$$