Question #158980

(talking about the apollo spacecraft, ignore air resistance) if the 28900kg Apollo 9 CSM sprays 2kg of urine out with a velocity of 20 m/s

a. what velocity would this give the spacecraft

b. over a period of 24 hours, by what distance would this change Apollo’s path?


1
Expert's answer
2021-01-28T20:10:53-0500

According to the momentum conservation law, the amount of momentum carried out by urine:


pu=2kg×20m/s=40kgm/sp_u = 2kg\times 20m/s = 40kg\cdot m/s

is equal to the change of Apollo's momentum:


maΔva=pum_a\Delta v_a = p_u

where ma=28900kgm_a = 28900kg is the mass of Apollo (neglecting the change of mass due to 2kg urine left), and Δva\Delta v_a is the change of its velocity:


Δva=pumaΔva=40kgm/s28900kg0.00138m/s\Delta v_a = \dfrac{p_u}{m_a}\\ \Delta v_a = \dfrac{40kg\cdot m/s}{28900kg} \approx 0.00138m/s

Over the period t=24h=86400st = 24h = 86400s this would change Apollo’s path by the following distance:


Δd=ΔvatΔd=0.0014m/s86400s119m\Delta d = \Delta v_at\\ \Delta d = 0.0014m/s\cdot 86400s \approx 119m

Answer. a) 0.00138m/s, b) 119m.


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