Question

A vertical wire with a diameter of 3.60 mm and an unstretched length of 4.25 m extends by a distance of 9.19 mm when it is loaded with a 60N weight.

Calculate the strain in the wire

Answer 1

By the definition of the strain, we get:

$$\epsilon=\dfrac{\Delta L}{L_0}=\dfrac{L-L0}{L_0},$$ $$\epsilon=\dfrac{4.25919\ m-4.25\ m}{4.25\ m}=2.16\cdot10^{-3}.$$