Answer to Question #158872 in Physics for Annie

Question

A student reads the mass on an electronic balance to be 1.34 g with 2% percentage uncertainty.

What is the correct measurement and uncertainty?

Answer 1

The absolute error (2% of 1.34 g) is:

$$\Delta m = 1.34g\cdot 0.02 \approx 0.03g$$

Thus, the correct reading is:

$$1.34g\pm\Delta m = 1.34g\pm0.03g$$

Answer. $1.34g\pm0.03g$.