Question #158811

. The stone with a mass of 200g is thrown up with an initial velocity V0 = 6 m / s. á) What happens to the Impulse during climbing, increases or decreases? Why? b) Calculate the change in momentum as the stone reaches its greatest height.


1
Expert's answer
2021-01-31T18:58:45-0500

a) Impulse decreases. It is from


mvfmvi=mgtmv_f-mv_i=-mgt

b)

Δp=mv=(0.2)(6)=1.2kgms\Delta p=-mv=-(0.2)(6)=-1.2\frac{kg\cdot m}{s}



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