Question

Hitting the hammer with the nail lasted delta t = 0.05 s. Calculate the impact force that acted on the nail, when it is known that the impulse of the hammer changed with delta p = 20 kgm / s.

Answer 1

$$F\Delta t=\Delta p,$$ $$F=\dfrac{\Delta p}{\Delta t}=\dfrac{20\ \dfrac{kgm}{s}}{0.05\ s}=400\ N.$$