The elastic stroke of the ping pong ball with a marble slab lasts delta t = 0.02 s. Calculate the impact force, knowing that the velocity of the strike ball was vo = 5 m / s.
The ball weight for pin pong "2.7\\ g=2.7\\cdot 10^{-3}\\ kg" .
"F=\\frac{mv-mv_0}{\\Delta t}=\\frac{|2mv_0|}{\\Delta t}=\\frac{2\\cdot2.7\\cdot10^{-3}\\cdot5}{0.02}=1.35\\ (N)" . Answer
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