Question

The elastic stroke of the ping pong ball with a marble slab lasts delta t = 0.02 s. Calculate the impact force, knowing that the velocity of the strike ball was vo = 5 m / s.

Answer 1

The ball weight for pin pong $2.7\ g=2.7\cdot 10^{-3}\ kg$ .

$F=\frac{mv-mv_0}{\Delta t}=\frac{|2mv_0|}{\Delta t}=\frac{2\cdot2.7\cdot10^{-3}\cdot5}{0.02}=1.35\ (N)$ . Answer