Calculate the momentum change for the box with mass m = 500 g during the delta time t = 0.5 s, when it is known that the coefficient of sliding friction is u = 0.1.
If only the force of friction acts on the body then
F=ΔpΔt→Δp=F⋅Δt=F=\frac{\Delta p}{\Delta t}\to \Delta p=F\cdot\Delta t=F=ΔtΔp→Δp=F⋅Δt=
=μmgt=0.1⋅0.5⋅9.8⋅0.5=0.245(kg⋅m/s)=\mu mgt=0.1\cdot0.5\cdot9.8\cdot 0.5=0.245(kg\cdot m/s)=μmgt=0.1⋅0.5⋅9.8⋅0.5=0.245(kg⋅m/s) . Answer
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