Calculate the momentum change for the box with mass m = 500 g during the delta time t = 0.5 s, when it is known that the coefficient of sliding friction is u = 0.1.
If only the force of friction acts on the body then
"F=\\frac{\\Delta p}{\\Delta t}\\to \\Delta p=F\\cdot\\Delta t="
"=\\mu mgt=0.1\\cdot0.5\\cdot9.8\\cdot 0.5=0.245(kg\\cdot m\/s)" . Answer
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