Question #158543

A stationary observer heard an ambulance’s frequency 25 Hz lower than the 750 Hz at which it is emitted. If the air temperature is 20.0°c, how fast is the ambulance going?


1
Expert's answer
2021-01-26T13:15:41-0500

The Doppler's effect equation gives

Δf=f0vc\Delta f=f_0\frac{v}{c}

Hence,


v=cΔff0=340m/s×25750=11.3m/sv=c\frac{\Delta f}{f_0}=\rm 340\: m/s\times\frac{25}{750}=11.3\: m/s


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