Answer to Question #158352 in Physics for Jireah Jane Magsayo

Question

A ball thrown 40 degrees angle below the horizontal at 8.0 m/s. After 0.40 seconds the horizontal component of its velocity will be?

Answer 1

If we ignore air resistance, the horizontal component of velocity is unchanged during the flight:

$$v_x=v\cdot\text{cos}40°=6.13\text{ m/s}.$$