A 2.2kg mass is whirled in a vertical circle of radius 1.8m at a uniform constant speed. calculate this speed if the minimum tension in the rope is 9.5N.
mg+N=mv2r→mg+N=m\frac{v^2}{r}\tomg+N=mrv2→
v=(N+mg)rm=(9.5+2.2⋅9.8)⋅1.82.2=5(m/s)v=\sqrt{\frac{(N+mg)r}{m}}=\sqrt{\frac{(9.5+2.2\cdot 9.8)\cdot1.8}{2.2}}=5(m/s)v=m(N+mg)r=2.2(9.5+2.2⋅9.8)⋅1.8=5(m/s) . Answer
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