Calculate the period of the Jupiter satellite Europa, when it is known that the radius of its orbit is about 600,000 km and the mass of Jupiter is M = 2 × 10²⁷kg.
mv2/r=GMm/r2→v2=GM/rmv^2/r=GMm/r^2\to v^2=GM/rmv2/r=GMm/r2→v2=GM/r
T=2πr/v→v=2πr/TT=2\pi r/v\to v=2\pi r/TT=2πr/v→v=2πr/T
(2πr/T)2=GM/r→(2\pi r/T)^2=GM/r\to(2πr/T)2=GM/r→
T=4π2r3GM=4⋅3.142⋅60000000036.67⋅10−11⋅2⋅1027=252702(s)=70.2(h)T=\sqrt{\frac{4\pi^2r^3}{GM}}=\sqrt{\frac{4\cdot 3.14^2\cdot 600000000^3}{6.67\cdot10^{-11}\cdot2\cdot10^{27}}}=252702(s)=70.2(h)T=GM4π2r3=6.67⋅10−11⋅2⋅10274⋅3.142⋅6000000003=252702(s)=70.2(h) .Answer
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