Answer to Question #157425 in Physics for Adibah Batrisyia

Question

 a man who with 55kg, on a skateboard. He had an

initial speed of 2.77m/s when descending the stairs at a height of 2m.

Calculate the man’s potential energy when his speed is 6m/s

Answer 1

$$E_p+0.5mv^2=mgh+0.5mv^2_0\\ E_p=mgh+0.5m(v^2_0-v^2)\\E_p=(55)(9.8)(2)+0.5(55)(2.77^2-6^2)=299\ J$$