Two forces F1 and F2 act on a particle. F1 has magnitude 5N and in direction 030° and F2 has magnitude 8N and in direction 090°. Find the magnitude and direction of their resultant. [ 11.36N; 067.6°
Fnet=(5cos30°)2+(5sin30°+8)2=11.36(N)F_{net}=\sqrt{(5\cos30°)^2+(5\sin30°+8)^2}=11.36(N)Fnet=(5cos30°)2+(5sin30°+8)2=11.36(N)
tanα=5sin30°+8)25cos30°=2,4248→α=67.6°\tan\alpha=\frac{5\sin30°+8)^2}{5\cos30°}=2,4248\to \alpha=67.6°tanα=5cos30°5sin30°+8)2=2,4248→α=67.6° . Answer
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