A diverging lens formed an image that is 20.0 cm in front of it. If the focal length
of the lens is 25 cm, where is the object placed?
"\\frac{1}{a}-\\frac{1}{b}=-\\frac{1}{f}\\to\\frac{1}{a}-\\frac{1}{0.2}=-\\frac{1}{0.25}"
"\\frac{1}{a}=1\\to a=1(m)" . Answer
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