Question #157239

A diverging lens formed an image that is 20.0 cm in front of it. If the focal length

of the lens is 25 cm, where is the object placed?


1
Expert's answer
2021-01-21T08:31:33-0500

1a1b=1f1a10.2=10.25\frac{1}{a}-\frac{1}{b}=-\frac{1}{f}\to\frac{1}{a}-\frac{1}{0.2}=-\frac{1}{0.25}


1a=1a=1(m)\frac{1}{a}=1\to a=1(m) . Answer

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