A dielectric of dielectric constant 5.0 is filled in the gap between the plates of a capacitor.calculate the factor by which the capacitance is increased,if the dielectric is only sufficient to fill up 1/5 of the gap.
C0=ϵ0SdC_0=\frac{\epsilon_0S}{d}C0=dϵ0S
C=C1+C2=ϵϵ0(1/5)Sd+ϵ0(4/5)Sd=C=C_1+C_2=\frac{\epsilon\epsilon_0(1/5)S}{d}+\frac{\epsilon_0(4/5)S}{d}=C=C1+C2=dϵϵ0(1/5)S+dϵ0(4/5)S=
=ϵ0Sd(ϵ/5+4/5)=\frac{\epsilon_0S}{d}(\epsilon/5+4/5)=dϵ0S(ϵ/5+4/5) .
k=CC0=ϵ/5+4/5=5/5+4/5=1.8k=\frac{C}{C_0}=\epsilon/5+4/5=5/5+4/5=1.8k=C0C=ϵ/5+4/5=5/5+4/5=1.8 .Answer
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