Question #156835

A long, straight wire of diameter 2.0mm carries a uniformly distributed current of 10A. At what distance from the axis of the wire will the magnitude of B vector be maximum.justify your answer


1
Expert's answer
2021-01-21T14:17:29-0500

For 0<r<R=2(mm)0<r<R=2(mm)


Bdl=μ0I\int Bdl=\mu_0I


B2πr=μ0IπR2πr2B=μ0I2πR2rB\cdot2\pi r=\mu_0\cdot \frac{I}{\pi R^2}\cdot\pi r^2\to B=\frac{\mu_0 I}{2\pi R^2}r


For r>Rr>R


B2πr=μ0IB=μ0I2πrB\cdot2\pi r=\mu_0 I\to B=\frac{\mu_0 I}{2\pi r}


So, B=Bmax=μ0I2πRB=B_{max}=\frac{\mu_0I}{2\pi R} if r=R=2(mm)r=R=2(mm) . Answer











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