An automobile makes a turn whose radius 18 m. The road is banked at an angle of
10o when the friction between the tires and the road is zero. At what speed should the driver take the curve to avoid sliding off the road?
Nsin10°=mv2rN\sin10°=m\frac{v^2}{r}Nsin10°=mrv2
Ncos10°−mg=0N\cos10°-mg=0Ncos10°−mg=0
So, we have
tan10°=v2gr\tan10°=\frac{v^2}{gr}tan10°=grv2
v=9.8⋅tan10°⋅18=5.58(m/s)v=\sqrt{9.8\cdot\tan10°\cdot 18}=5.58(m/s)v=9.8⋅tan10°⋅18=5.58(m/s) . Answer
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments