Question

Find the downward force applied 25 cm from the axis of rotation when the torque is found to be 23.75 Nm

Answer 1

By definition, the torque $\tau$ is the product of the force $F$ and the distance of the force application $r$ (if they are perpendicular). Thus, oobtain:

$$\tau = Fr$$

Since $\tau = 23.75\space N\cdot m$, and $r = 0.25m$, obtain the force:

$$F = \dfrac{\tau}{r} = \dfrac{23.75\space N\cdot m}{0.25m} = 95N$$

Answer. 95 N.