Question #155979

Calculate the potential energy of a 4.5 kg bowling ball that is on the ground. Assume that g = 9.8 m/s2


1
Expert's answer
2021-01-15T13:46:34-0500

By the definition of the potential energy, we have:


PE=mgh=4.5 kg9.8 ms20 m=0.PE=mgh=4.5\ kg\cdot9.8\ \dfrac{m}{s^2}\cdot 0\ m=0.

Answer:

PE=0.PE=0.


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