Question

Determine the magnitude and direction of the electromagnetic force between the two charges 66 and -22 separated by the distance 45.

Answer 1

$$F=k\frac{q_1q_2}{r^2}\\ F=9\cdot10^9\frac{(66)(-22)}{(45)^2}=-6.45\cdot10^9N$$

Negative sign means that the force is attractive.