Question #155624

The weight of a body at rest is 600 N. When the body is in the elevator it has a weight P = 780 N. Determine: a. the acceleration with which the elevator moves. b. The direction of the elevator movement and the type of elevator movement.


1
Expert's answer
2021-01-21T13:02:06-0500

a) Let's apply the Newton's Second Law of Motion:


Pmg=ma,P-mg=ma,a=Pmgm,a=\dfrac{P-mg}{m},a=780 N600 N600 N9.8 ms2=2.94 ms2.a=\dfrac{780\ N-600\ N}{\dfrac{600\ N}{9.8\ \dfrac{m}{s^2}}}=2.94\ \dfrac{m}{s^2}.

b) The sign plus means that the elevator moves upward.

Answer:

a) a=2.94 ms2.a=2.94\ \dfrac{m}{s^2}.

b) The sign plus means that the elevator moves upward.


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