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Answer to Question #155568 in Physics for Shukroh
Question #155568
A simple pendulum has a period of 512s. When the length is shorten by 2m, it’s period is 128s. Calculate the original length of the pendulum
Expert's answer
"T=2\\pi \\sqrt{\\frac{l}{g}}\\\\\n\\frac{512}{128}= \\sqrt{\\frac{l}{l-2}}\\\\l=2.13\\ m"
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