Question #155493

The period of oscillation for a mass on a spring system is 0.22 s. If m=3.5 kg, what is the spring

constant of the spring?


1
Expert's answer
2021-01-14T10:38:12-0500

We can find the spring constant of the spring from the formula:


T=2πmk,T=2\pi\sqrt{\dfrac{m}{k}},T2=4π2mk,T^2=4\pi^2\dfrac{m}{k},k=4π2mT2,k=\dfrac{4\pi^2m}{T^2},k=4π23.5 kg(0.22 s)2=2855 Nm.k=\dfrac{4\pi^2\cdot 3.5\ kg}{(0.22\ s)^2}=2855\ \dfrac{N}{m}.

Answer:

k=2855 Nm.k=2855\ \dfrac{N}{m}.


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