An object initially traveling at 30. m/s south accelerates uniformly at 5.0 m/s/s north and is displaced 10 meters. The final velocity of the object is....
The velocity of an object under a constant acceleration is given as follows:
where is the initial speed, is the acceleration, is the time of motion. Sign minus here is due to the opposite directions of the initial velocity and acceleration (south and north respectively).
The distance travelled by the object is given as follows:
Solving the quadratic equation for , obtain:
Substituting into the first equation, obtain:
Answer. -28.3 m/s.
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