The car with mass m = 1.2 t passes at a speed of 20 km / h through a bridge bent down. Calculate the force with which the compression machine bridges to the lowest point, when it is known that the radius of the bridge is R = 10 m.
mg−N=−mv2r→N=mg+mv2r=mg-N=-m\frac{v^2}{r}\to N=mg+m\frac{v^2}{r}=mg−N=−mrv2→N=mg+mrv2=
=1200⋅9.8+1200⋅5.56210=15464(N)=1200\cdot9.8+1200\cdot\frac{5.56^2}{10}=15464(N)=1200⋅9.8+1200⋅105.562=15464(N) . Answer
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments