Question

Cupid is hovering in the air when he shoots an arrow giving it a horizontal velocity of 14 m/s. If the arrow covers a horizontal displacement of 17 m before landing on the ground, from what height was the arrow shot from Cupid’s bow?

Answer 1

Let's first find the time that the arrow takes to reach the ground:

$$x=v_0t,$$ $$t=\dfrac{x}{v_0}=\dfrac{17\ m}{14\ \dfrac{m}{s}}=1.21\ s.$$

Finally, we can find the height from which the arrow was shot:

$$y=\dfrac{1}{2}gt^2,$$ $$y=\dfrac{1}{2}\cdot 9.8\ \dfrac{m}{s^2}\cdot(1.21\ s)^2=7.2\ m.$$

Answer:

$y=7.2\ m.$