Answer to Question #155062 in Physics for John Mark Bongcayao

Question

What is the Power of a rechargeable flashlight used by a lookout if it 

uses 60,000J for 50min?

Answer 1

By the definition of the power, we have:

$$P=\dfrac{W}{t}=\dfrac{60000\ J}{50\ min\cdot(\dfrac{60\ s}{1\ min})}=20\ W.$$

Answer:

$P=20\ W.$