Answer to Question #155062 in Physics for John Mark Bongcayao

Question #155062

What is the Power of a rechargeable flashlight used by a lookout if it

uses 60,000J for 50min?

Expert's answer

By the definition of the power, we have:

P=\dfrac{W}{t}=\dfrac{60000\ J}{50\ min\cdot(\dfrac{60\ s}{1\ min})}=20\ W.

Answer:

$P=20\ W.$

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