Question #154997

What is the net force on a 45 kg bike accelerating at 2.4 m/s



1
Expert's answer
2021-01-11T16:35:13-0500

By the Newton's Second Law of Motion, we have:


Fnet=ma=45 kg2.4 ms2=108 N.F_{net}=ma=45\ kg\cdot2.4\ \dfrac{m}{s^2}=108\ N.

Answer:

Fnet=108 N.F_{net}=108\ N.


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