Question

The Kinetic Energy of a 0.5-kg monkey fist moving at 5m/s is

Answer 1

By the definition of the kinetic energy, we have:

$$KE=\dfrac{1}{2}mv^2=\dfrac{1}{2}\cdot 0.5\ kg\cdot(5.0\ \dfrac{m}{s})^2=6.25\ J.$$

Answer:

$KE=6.25\ J.$