Answer to Question #154800 in Physics for Shalize Dookie

Question #154800

Upon entering a straight section of highway, Batman accelerates the Batcycle for 7.50 s, increasing its velocity from 24 m/s [S] to 38 m/s [S]. Calculate the Batcycle’s displacement while accelerating. 


1
Expert's answer
2021-01-14T10:40:46-0500

Let's first find the acceleration of the Batcycle:


a=vv0t=38 ms24 ms7.5 s=1.86 ms2.a=\dfrac{v-v_0}{t}=\dfrac{38\ \dfrac{m}{s}-24\ \dfrac{m}{s}}{7.5\ s}=1.86\ \dfrac{m}{s^2}.

Finally, we can find the Batcycle’s displacement from the kinematic equation:


d=v0t+12at2,d=v_0t+\dfrac{1}{2}at^2,d=24 ms7.5 s+121.86 ms2(7.5 s)2=232.3 m.d=24\ \dfrac{m}{s}\cdot 7.5\ s+\dfrac{1}{2}\cdot 1.86\ \dfrac{m}{s^2}\cdot(7.5\ s)^2=232.3\ m.

Answer:

d=232.3 m.d=232.3\ m.


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