Question

how much kinetic energy does a 2500kg minivan traveling at 35m/s have?

Answer 1

By the definition of the kinetic energy, we have:

$$KE=\dfrac{1}{2}mv^2=\dfrac{1}{2}\cdot 2500\ kg\cdot(35\ \dfrac{m}{s})^2=1.53\cdot10^6\ J.$$

Answer:

$KE=1.53\cdot10^6\ J.$