A uniform cone of mass 2.0 kg and of height 40 cm, resting on its base, of width 30 cm. Calculate:
i) the minimum horizontal pull to the apex which can be applied to raise the edge from the floor.
τ1−τ2=0→mg⋅(0.32)−F⋅(0.4)=0\tau_1-\tau_2=0\to mg\cdot (\frac{0.3}{2})-F\cdot(0.4)=0τ1−τ2=0→mg⋅(20.3)−F⋅(0.4)=0
F=mg⋅(0.32)0.4=2⋅9.8⋅(0.32)0.4=7.35(N)F=\frac{mg\cdot (\frac{0.3}{2})}{0.4}=\frac{2\cdot 9.8\cdot (\frac{0.3}{2})}{0.4}=7.35(N)F=0.4mg⋅(20.3)=0.42⋅9.8⋅(20.3)=7.35(N) . Answer
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