Question #154039

During a head-on car crash, a passenger in the front seat of the car accelerates from 13.0 m/s to rest in 0.10 seconds. The passenger is holding a 20.9 kg child on her lap. The passenger is wearing a seat belt, but the child is not. What force must the passenger exert on the child to prevent the child from smashing into the dashboard or windshield?


1
Expert's answer
2021-01-07T10:56:39-0500

During the incendent the passenger (and the child as well) experienced the following force:


F=maF = ma

where m=20.9kgm = 20.9kg is the mass of the child, and aa is her acceleration. By definition, the acceleration is:


a=vta = \dfrac{v}{t}

where v=13m/sv = 13m/s is her initial speed, and t=0.1st = 0.1s is the time she comes to rest. The force the the passenger must exert on the child is equal and opposite to the force FF. Thus, obtain:


F=mvtF=20.9130.1=2717NF = \dfrac{mv}{t}\\ F = \dfrac{20.9\cdot 13}{0.1} = 2717N

Answer. 2717 N.


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