Question #154039

During a head-on car crash, a passenger in the front seat of the car accelerates from 13.0 m/s to rest in 0.10 seconds. The passenger is holding a 20.9 kg child on her lap. The passenger is wearing a seat belt, but the child is not. What force must the passenger exert on the child to prevent the child from smashing into the dashboard or windshield?


Expert's answer

During the incendent the passenger (and the child as well) experienced the following force:


F=maF = ma

where m=20.9kgm = 20.9kg is the mass of the child, and aa is her acceleration. By definition, the acceleration is:


a=vta = \dfrac{v}{t}

where v=13m/sv = 13m/s is her initial speed, and t=0.1st = 0.1s is the time she comes to rest. The force the the passenger must exert on the child is equal and opposite to the force FF. Thus, obtain:


F=mvtF=20.9130.1=2717NF = \dfrac{mv}{t}\\ F = \dfrac{20.9\cdot 13}{0.1} = 2717N

Answer. 2717 N.


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