Answer to Question #153194 in Physics for ian

Question

A 5kg block was placed on an inclined plane(50 degrees with respect to the vertical).Forces A is at angle C with respect to the horizontal. Force B is parallel with the incline.The coefficients of static and kenetic friction are 0.3 and 0.2 respectively.

A=197KN

B=49 KN

C=7 degrees

A.DETERMINE IF THERE IS MOTION AND ITS DIRECTION

B.BASED ON YOUR ANSWER IN "A" WHAT IS THE ACCELERATION OF THE BLOCK?

Answer 1

A.

$N=mg\cos40°+197000\cdot\sin47°=5\cdot9.8\cdot\cos40°+197000\cdot\sin47°=$

$=144114(N)$

$49000+mg\sin40°-197000\cos47°=49000+5\cdot9.8\cdot\sin40°-197000\cos47°=$

$=-85322(N)$

$F_f=0.3N=0.3\cdot144114=43234(N)$

$F_{total}=-85322+43234=-42088(N)$

The block will move up the inclined plane. Answer

B.

$a=F/m=42088/5=8418(m/s^2)$ . Answer