Answer to Question #153138 in Physics for Muhammad Kashif

Question #153138
A positive particle of charge 1C accelerates in a uniform electric field of 100 V/m. The particle started from rest on an equipotential plane of 50V. After t=0.0002 seconds, the particle is on an equipotential plane of 10V. Determine the distance travelled by the particle?
1
Expert's answer
2020-12-29T15:32:47-0500

"q\\Delta U=mv^2\/2\\to v^2=2q\\Delta U\/m"


"qE=ma\\to a=qE\/m"


"s=\\frac{v^2}{2a}=\\frac{2q\\Delta Um}{2mqE}=\\Delta U\/E=(50-10)\/100=0.4(m)"






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