The distance traveled under the constant acceleration a=3.2m/s2a = 3.2m/s^2a=3.2m/s2 in time t=32.8st = 32.8st=32.8s is (assume starting from rest):
Answer. 1721 m.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments