Question #152501
An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.
1
Expert's answer
2020-12-23T10:25:13-0500

The distance traveled under the constant acceleration a=3.2m/s2a = 3.2m/s^2 in time t=32.8st = 32.8s is (assume starting from rest):


d=at22d=3.232.8221721md = \dfrac{at^2}{2}\\ d = \dfrac{3.2\cdot 32.8^2}{2} \approx 1721m

Answer. 1721 m.


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