Question

The length of a spring is 40cm and its constant is half a newton per centimeter. If we tie a weight of half a kilogram to the end of it and pull it up at a Acceleration of 4m/s², what will be the length of the spring?

Answer 1

$l_0=0.4(m)$

$k=500(N/m)$

$k\Delta x_0=mg\to \Delta x_0=mg/k=0.5\cdot9.8/500=0.0098(m)$

$k\Delta x=ma\to \Delta x=ma/k=0.004(m)$

The length of the spring

$l=l_0+\Delta x_0+\Delta x=0.4+0.0098+0.004=0.4138(m)=41.38(cm)$ . Answer